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Home » = 2^4 \times 3,\quad 72 = 2^3 \times 3^2 - Crosslake

= 2^4 \times 3,\quad 72 = 2^3 \times 3^2 - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📝 Recent Posts

$ P(0) = \binom{6}{0} (0.3)^0 (0.7)^6 = 1 \cdot 1 \cdot 0.117649 = 0.1...
$ P(1) = \binom{6}{1} (0.3)^1 (0.7)^5 = 6 \cdot 0.3 \cdot 0.16807 = 0....
$ P(2) = \binom{6}{2} (0.3)^2 (0.7)^4 = 15 \cdot 0.09 \cdot 0.2401 = 0...
P(X < 3) = 0.117649 + 0.302526 + 0.324135 = 0.74431
\boxed{0.74431}
Question: A mix of 5 AI models and 3 human analysts sit around a circu...
Solution: For circular arrangements of $ n $ distinguishable people, t...
Here, we have $ 5 + 3 = 8 $ distinguishable individuals.
So, the number of distinct circular arrangements is:
Thus, the number of distinct seating arrangements is:

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