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Home » \[ 6p + q = 7 \quad \text(E4) \] - Crosslake

\[ 6p + q = 7 \quad \text(E4) \] - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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A company produces 500 units of a product in 5 days. If production inc...
Daily production for the first 5 days is \( \frac{500}{5} = 100 \) uni...
On the sixth day, production increases by 20%: \(100 + 0.2 \times 100...
On the seventh day, production again increases by 20%: \(120 + 0.2 \ti...
#### 144 units
The length of a diagonal of a square is 10 cm. What is the perimeter o...
The diagonal \(d\) of a square with side \(s\) is given by \(d = s\sqr...
Solving for \(s\), we have \(s = \frac{10}{\sqrt{2}} = \frac{10 \times...
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\gcd(a^m - 1, a^n - 1) = a^{\gcd(m,n)} - 1, \quad ext{for } a > 1.
\gcd(3^{15} - 1, 3^9 - 1) = 3^{\gcd(15,9)} - 1.
Now compute $\gcd(15,9) = 3$.
\gcd(3^{15} - 1, 3^9 - 1) = 3^3 - 1 = 27 - 1 = 26.
Therefore, the greatest common divisor is $oxed{26}$.**Question:** An...
Solution:** Start with the given equation:
rac{x+y}{x-y} + rac{x-y}{x+y} = 3.
Let \( u = rac{x+y}{x-y} \), so the second term becomes \( rac{1}{u}...
u + rac{1}{u} = 3.
Multiply both sides by \(u\) (assuming \(u

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