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Home » A = A_ extsector - A_ exttriangle = rac16\pi3 - 6\sqrt3 - Crosslake

A = A_ extsector - A_ exttriangle = rac16\pi3 - 6\sqrt3 - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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A = \frac{\theta}{360} \cdot \pi r^2
Substitute $ r = 12 $, $ \theta = 60^\circ $:
A = \frac{60}{360} \cdot \pi \cdot 144 = \frac{1}{6} \cdot 144\pi = 24...
The area of the visual sector is $ \boxed{24\pi} $ m².Question: A biol...
We are given that the clutch size $ n $ satisfies:
n \equiv 1 \pmod{7} \quad \text{and} \quad n \equiv 1 \pmod{11}
This implies:
n - 1 \equiv 0 \pmod{7} \quad \text{and} \quad n - 1 \equiv 0 \pmod{11...
So $ n - 1 $ is a common multiple of 7 and 11. Since 7 and 11 are copr...
\text{lcm}(7, 11) = 7 \cdot 11 = 77

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