A ball is thrown upwards with an initial velocity of 20 m/s from a height of 50 meters. Using the equation \( h(t) = -5t^2 + 20t + 50 \), where \( h \) is the height in meters and \( t \) is the time in seconds, find the time when the ball hits the ground. - Crosslake
Mar 01, 2026
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