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Home » A_\texttriangle = \frac12ab = r \cdot s - Crosslake

A_\texttriangle = \frac12ab = r \cdot s - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 \( 1165 = 1000 \left(1 + \frac{r}{100}\right) \)

📌 \( 1.165 = 1 + \frac{r}{100} \)

📌 \( \frac{r}{100} = 0.165 \)

📌 \( r = 16.5\% \)

📌 Simplify the expression \( (3x^2 - 2x + 4) - (x^2 + 3x - 5) \).

📌 Distribute the negative sign:

📌 \( 3x^2 - 2x + 4 - x^2 - 3x + 5 \)

📌 \( (3x^2 - x^2) + (-2x - 3x) + (4 + 5) = 2x^2 - 5x + 9 \)

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\( x = 4 \) or \( x = -2 \).
But \( x > 2 \) for log to be defined, so \( x = 4 \).
The solution is \( x = 4 \).
Question**: A rectangle has a perimeter of 48 cm and a length that is...
Let width = \( w \), length = \( 2w \).
Perimeter: \( 2(w + 2w) = 48 \Rightarrow 6w = 48 \Rightarrow w = 8 \).
Length = \( 16 \) cm.
Area = \( 8 imes 16 = 128 \) cmÂ².
The area is 128 cmÂ².
Question**: Evaluate \( \lim_{x o 2} rac{x^2 - 4}{x - 2} \).

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