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Home » \boxed9 + 4\sqrt2 - Crosslake

\boxed9 + 4\sqrt2 - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 A_{\text{circle}} = \pi r^2

📌 Area of the Square:

📌 The side length of the square is \( 2r \), so its area is:

📌 A_{\text{square}} = (2r)^2 = 4r^2

📌 Ratio of Areas:

📌 The ratio of the area of the circle to the area of the square is:

📌 \text{Ratio} = \frac{A_{\text{circle}}}{A_{\text{square}}} = \frac{\pi r^2}{4r^2} = \frac{\pi}{4}

📌 Thus, the ratio of the area of the circle to the area of the square is \(\boxed{\frac{\pi}{4}}\).

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