But as \( x \to 0^+ \), \( 5000/x \to \infty \); as \( x \to \infty \), \( -0.5x \to -\infty \), but \( 5000/x \to 0 \), so \( P(x) \to -\infty \)? That's impossible. - Crosslake
Mar 01, 2026
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