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Home » C(4) = 50 × e^(-0.2×4) = 50 × e^(-0.8) - Crosslake

C(4) = 50 × e^(-0.2×4) = 50 × e^(-0.8) - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 There are 11 such numbers. Since there are 50 positive integers less than or equal to 50, the probability is:

📌 \frac{11}{50} = \boxed{\frac{11}{50}}

📌 Question: Solve for $ z $ in the equation $ 3(z - 4) + 7 = 2(4z + 1) $.

📌 3z - 12 + 7 = 8z + 2

📌 3z - 5 = 8z + 2

📌 Now move all terms involving $ z $ to one side and constants to the other:

📌 3z - 8z = 2 + 5

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Subtract (iv) from (v):
Substitute into (iv):
6(2889) + b = 18 \Rightarrow 17334 + b = 18 \Rightarrow b = -17316
Substitute $ a = 2889 $, $ b = -17316 $ into (i):
7(2889) + 3(-17316) + c = 38 \Rightarrow 20223 - 51948 + c = 38 \Right...
Now use (1):
- 17316 + 31725 + d = 20 \Rightarrow (2889 - 17316) = -14427, \quad -1...
\Rightarrow 17298 + d = 20 \Rightarrow d = -17278
Thus, $ E(0) = d = -17278 $.
\boxed{-17278}

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