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Home » Doubling every 5 years → number of doublings in 15 years = 15 / 5 = 3 - Crosslake

Doubling every 5 years → number of doublings in 15 years = 15 / 5 = 3 - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 2x + 3\left(-\frac{32}{11}\right) = -6 \\

📌 2x - \frac{96}{11} = -6 \\

📌 2x = -6 + \frac{96}{11} = \frac{-66 + 96}{11} = \frac{30}{11} \\

📌 x = \frac{15}{11}

📌 Thus, the intersection point is $ \left( \frac{15}{11}, -\frac{32}{11} \right) $.

📌 Final answer: $ \boxed{\left( \frac{15}{11}, -\frac{32}{11} \right)} $

📌 Question: Factor the expression $ 16x^4 - 81y^4 $.

📌 Recognize this as a difference of squares:

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