From the second equation: $v_3 = \frac32v_1$. From the third equation: $v_1 + 2v_2 = 2 \Rightarrow v_1 = 2 - 2v_2$. Substitute into the first equation: $3v_2 + \frac32(2 - 2v_2) = 3 \Rightarrow 3v_2 + 3 - 3v_2 = - Crosslake