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Home » g(x) = ax^3 + bx^2 + cx + d - Crosslake

g(x) = ax^3 + bx^2 + cx + d - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Nous avons \(3 = (1 + r)^7\).
En prenant le logarithme : \(\log(3) = 7 \log(1 + r)\)
\(\log(1 + r) = \frac{\log(3)}{7} \approx \frac{0,4771}{7} \approx 0,0...
Donc, \(1 + r \approx 10^{0,06816} \approx 1,175\)
Ainsi, \(r \approx 0,175 = 17,5\%\)
Un vulgarisateur scientifique explique la dépréciation d'un équipement...
Montant à amortir : \(10\,000 - 1\,000 = 9\,000\) dollars.
Amortissement annuel : \(\frac{9\,000}{10} = 900\) dollars.
Chaque année, 900 dollars sont déduits.

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