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Home » I Wasn’t Expecting This—Now I’m Heartbroken Over Your Love! - Crosslake

I Wasn’t Expecting This—Now I’m Heartbroken Over Your Love! - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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A: $t = 1$
B: $t = 0.5$
C: $t = 2$
D: $t = \sqrt{2}$
Compute $t$ such that $\langle 2t, t^2 \rangle \cdot \langle 1, -1 \ra...
Option B: $2t - t^2 = 0$ → $t(2 - t) = 0$, so $t = 2$ is valid non-zer...
All steps confirm the solution is valid.
Thus, the correct choice is $\boxed{B}$.
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2x^2 - 3x + 1 = 0
Solve the quadratic:
x = \frac{3 \pm \sqrt{9 - 8}}{4} = \frac{3 \pm 1}{4} \Rightarrow x = 1...
Now solve for $z$:
$\sin z = 1 \Rightarrow z = 90^\circ$
$\sin z = \frac{1}{2} \Rightarrow z = 30^\circ, 150^\circ$
Thus, the solutions are:
\boxed{30^\circ, 90^\circ, 150^\circ}
Question: Find the value of $x$ so that the vectors $\begin{pmatrix} 2...
Two vectors are orthogonal if their dot product is zero:

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