Solution: Let $\mathbfv = \beginpmatrix v_1 \\ v_2 \\ v_3 \endpmatrix$. The cross product $\mathbfv \times \mathbfw$ is $\beginpmatrix 3v_2 + v_3 \\ 2v_3 - 3v_1 \\ -v_1 - 2v_2 \endpmatrix = \beginpmatrix 3 \\ 0 \\ -2 \endpmatrix$. This gives the system: - Crosslake