Solution: The slope forms a right triangle with opposite side 1 and adjacent side $ \sqrt3 $. Thus, $ \tan \theta = \frac1\sqrt3 = \boxed\frac\sqrt33 $.Question: What is the remainder when the sum $ 1^3 + 2^3 + 3^3 + \dots + 10^3 $ is divided by 9? - Crosslake