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Home » Substitute \( a = 1 \) back into \( 3a + b = 5 \): - Crosslake

Substitute \( a = 1 \) back into \( 3a + b = 5 \): - Crosslake

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Mar 01, 2026

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\[ 990 = 110 + (n-1) \times 11 \]
\[ 880 = (n-1) \times 11 \]
\[ n-1 = 80 \]
\[ n = 81 \]
Thus, there are \(\boxed{81}\) 3-digit numbers divisible by 11.
Question:** Solve for \(x\) in the equation \(3x - 5 = 2x + 7\).
Start by isolating \(x\) on one side of the equation. Subtract \(2x\)...
\[ 3x - 2x - 5 = 7 \]
\[ x - 5 = 7 \]
Add 5 to both sides to solve for \(x\):

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