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Home » Substitute: \(A = 1000(1 + \frac0.054)^4 \times 2\). - Crosslake

Substitute: \(A = 1000(1 + \frac0.054)^4 \times 2\). - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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From (2):
2p + q = 2 \quad ext{(ii)}
+ q = 3 \Rightarrow q = 4
Now verify with (3):
h(3) = 27 + 3(-1) + 4 = 27 - 3 + 4 = 28
e 24
Contradiction! So our assumption that \( h(x) = x^3 + px + q \) (missi...
Wait â perhaps \( h(x) = x^3 + px + q \), but we must use all three...
But let's suppose the model is \( h(x) = ax^3 + px + q \), as cubic wi...
h(1) = a(1)^3 + p(1) + q = a + p + q = 4 \quad ext{(1)}

📝 Recent Posts

Break-even point: Revenue = Cost
75x = 50x + 2000
25x = 2000
x = 2000 / 25
x = 80
Let the integers be x, x+1, x+2.
x + (x + 1) + (x + 2) = 72
3x + 3 = 72
3x = 69
x = 23

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