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Home » Time for second part: \( \frac20080 = 2.5 \) hours. - Crosslake

Time for second part: \( \frac20080 = 2.5 \) hours. - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Since \( x > 1 \), \( x = \frac{1 + \sqrt{33}}{2} \)
#### \(\frac{1 + \sqrt{33}}{2}\)
A circle is inscribed in a square with side length 8 units. Find the a...
Radius of the circle: \( \frac{8}{2} = 4 \)
Area of the circle: \( \pi r^2 = \pi \times 4^2 = 16\pi \)
#### \(16\pi\)
Solve for \( x \) in the equation \( 3^{2x} = 81 \).
\( 81 = 3^4 \)
\( 3^{2x} = 3^4 \)
\( 2x = 4 \)

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