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Home » \(u' = 2t\), \(v' = e^t\). - Crosslake

\(u' = 2t\), \(v' = e^t\). - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 This value is achievable when $ x = y = z $, so the minimum is

📌 oxed{3 - \log 2}.

📌 Question: Find the remainder when $ (x^2 + 1)^{2025} + 1 $ is divided by $ x^4 + x^2 + 1 $.

📌 Let $ f(x) = (x^2 + 1)^{2025} + 1 $, and we are to find the remainder when $ f(x) $ is divided by $ x^4 + x^2 + 1 $.

📌 Let $ d(x) = x^4 + x^2 + 1 $. Note that

📌 x^6 - 1 = (x^2 - 1)(x^4 + x^2 + 1),

📌 so $ x^6 \equiv 1 \pmod{d(x)} $. Thus, modulo $ d(x) $, all powers of $ x $ reduce modulo 6.

📌 We reduce $ f(x) \equiv (x^2 + 1)^{2025} + 1 \pmod{d(x)} $.

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