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Home » The eigenvalues \( \lambda \) are found by solving the characteristic equation: - Crosslake

The eigenvalues \( \lambda \) are found by solving the characteristic equation: - Crosslake

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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a(2)^2 + b(2) + c &= 11, \\
a(3)^2 + b(3) + c &= 18.
a + b + c &= 6, \\
4a + 2b + c &= 11, \\
9a + 3b + c &= 18.
Now, we solve the system:
3a + b &= 5, \\
5a + b &= 7.
Substitute \( a = 1 \) back into \( 3a + b = 5 \):
3(1) + b = 5 \implies b = 2.

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